Tank Cone Bottom
![]() 175 gallon cone bottom tank and stand US $440.00
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![]() 310 gallon cone bottom tank and stand US $530.00
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![]() 30 gallon cone bottom tank only 24" X 28" NO STAND US $83.00
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![]() 35 gallon cone bottom tank only 23" X 29" NO STAND US $74.99
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![]() 30 Gallon Cone Bottom Tank Full Drain w/ steel Stand US $214.83
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![]() 30 Gallon Cone Bottom Tank Full Drain US $115.40
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![]() 15 Gallon Cone Bottom Tank Full Drain US $89.33
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![]() 150 Gallon Stainless Steel Tank cone bottom in SC US $1,550.00
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![]() 60 gallon cone bottom tank only 24" X 42" NO STAND US $102.00
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![]() 20,000 Gallon Carbon Steel Tank Silo w Cone Bottom - 5 in Stock! US $17,500.00
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![]() 150 gallon Stainless Steel TANK cone bottom open top US $950.00
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![]() 2,500 Gallon Cone Bottom Tank US $999.00
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![]() 6000 gallon cone bottom tank ONLY NO stand US $4,565.00
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![]() 15 gallon cone bottom tank only 24" X 21" NO STAND US $70.00
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![]() 1050 gallon cone bottom tank and stand US $1,135.00
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![]() 60 Gallon Cone Bottom Tank Full Drain US $150.81
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![]() 725 GAL FIBERGLASS TANK cone bottom open top US $450.00
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![]() 1200 Gallon offset cone bottom open top tank with mix US $12,500.00
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![]() 1030 CU.FT Aluminum SILO Tank 8' dia. x 20' T/T with 6'3" Cone Bottom in TX US $12,500.00
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![]() 1600 gallon cone bottom tank and stand US $1,620.00
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![]() 16 Gallon stainless steel cone bottom lab mix tank US $1,600.00
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![]() 18.5 Gallon stainless steel cone bottom lab mix tank US $1,600.00
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![]() 16 Gallon stainless steel cone bottom tank lab mix tank US $1,600.00
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![]() 2500 gallon cone bottom tank and stand US $2,323.00
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Applied Calc question?
A tank in the shape of an inverted right circular cone (so that the point is at the bottom) has height 9 meters and radius 11 meters. It is filled with 4 meters of hot chocolate.
Find the work required to empty the tank by pumping the hot chocolate over the top of the tank. Note: the density of hot chocolate is = 1450 kg/m^3, and since the measurements are metric, you need to multiply the mass being lifted by 9.8 to convert it to weight.
First give the integrand to be evaluated, expressed in terms of h, the height from the bottom of the inverted cone.
W = (1450) (9.8) ∫ (9 - h) π (11/9)² h² dh [0,4]
= 220084480 π / 81 J
Answer: 220084480 π / 81 J ........ ≈ 8535997.35 J
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