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Probability Help?
According to the National Health and Nutrition Examination Survey, the serum total cholesterol level of US females 20 years old or older is normally distributed with a mean of 206 mg/dL and a standard deviation of 44.7 mg/dL.
1. Determine the probability of a randomly selected female having a level between 150 mg/dL and 250 mg/dL
2. Determine the probability of a randomly selected female having a level greater than 220 mg/dL
I think I am supposed to use the Normal table with the equation z = (x - mu) / std dev?
Yes, this is the approach exactly, You have m=206, stddev=44.7:
1) P(150 < x < 250) = P(150 - 206 < x - m < 250 - 206) =
= P(-56/44.7 < z < 44/44.7) ≈ P( -1.25 < z < 0.98) ≈
≈ 0.84 - (1 - 0.89) ≈ 0.73 /rounded to the 2nd digit after the dec. point; You can work with greater accuracy of course/
2) P(x > 220) = P(x - m > 14) = P(14/44.7 < z < infinity) ≈
≈ 1 - 0.62 ≈ 0.38
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